今日积累-小程序提示Can‘t find variable: TextDecoder的解决方案，终极_can\'t find variable: textdecoder

创建一个convertjs.js在小程序某个角落

内容

// TextDecoder polyfillif (typeof TextDecoder === \'undefined\') { class TextDecoder { constructor(encoding = \'utf-8\') { this.encoding = encoding.toLowerCase(); } decode(dataView) { let data; if (dataView instanceof ArrayBuffer) { data = new Uint8Array(dataView); } else if (dataView instanceof Uint8Array) { data = dataView; } else { throw new Error(\'参数必须是 ArrayBuffer 或 Uint8Array\'); } if (this.encoding === \'utf-8\') { return this._decodeUTF8(data); } else { throw new Error(\'当前只支持 UTF-8 编码\'); } } _decodeUTF8(data) { let str = \'\'; let i = 0; while (i < data.length) { let byte1 = data[i]; let char; // ASCII 字符 if (byte1 < 0x80) { char = String.fromCharCode(byte1); i += 1; } // 2字节序列 else if (byte1 < 0xE0) { const byte2 = data[i + 1]; char = String.fromCharCode(((byte1 & 0x1F) << 6) | (byte2 & 0x3F)); i += 2; } // 3字节序列 else if (byte1 < 0xF0) { const byte2 = data[i + 1]; const byte3 = data[i + 2]; char = String.fromCharCode( ((byte1 & 0x0F) << 12) | ((byte2 & 0x3F) << 6) | (byte3 & 0x3F) ); i += 3; } // 4字节序列 else { const byte2 = data[i + 1]; const byte3 = data[i + 2]; const byte4 = data[i + 3]; let codepoint = ((byte1 & 0x07) << 18) | ((byte2 & 0x3F) << 12) | ((byte3 & 0x3F) <> 10) + 0xD800; const lowSurrogate = (codepoint & 0x3FF) + 0xDC00; char = String.fromCharCode(highSurrogate, lowSurrogate); i += 4; } str += char; } return str; } } // 全局注入 TextDecoder globalThis.TextDecoder = TextDecoder;}

在app.js中 

 import \'./utils/convertjs\'

然后使用的位置

const decoder = new TextDecoder(\'utf-8\');const utf8String = decoder.decode(arrayBuffer);

这样就实现将中文乱码转化成utf-8的中文了